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A.P.  Qno.1

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Asked by hariom2083 14th August 2018, 1:10 PM
Answered by Expert
Answer:
begin mathsize 18px style straight l space first space term
straight m space equals space straight l plus 4 straight d
straight m minus straight l equals 4 straight d
straight d equals fraction numerator straight m minus straight l over denominator 4 end fraction
now comma
let space number space of space terms space be space straight t
straight n space equals straight l plus open parentheses straight t minus 1 close parentheses straight d
fraction numerator straight n minus straight l over denominator straight d end fraction equals straight t minus 1
straight t equals 1 plus fraction numerator straight n minus straight l over denominator straight d end fraction
straight t equals space fraction numerator straight d plus straight n minus straight l over denominator straight d end fraction equals fraction numerator fraction numerator straight m minus straight l over denominator 4 end fraction plus straight n minus straight l over denominator fraction numerator straight m minus straight l over denominator 4 end fraction end fraction equals fraction numerator straight m plus 4 straight n minus 5 straight l over denominator straight m minus straight l end fraction
now
straight s subscript straight t equals straight t over 2 open parentheses straight n plus straight l close parentheses
equals fraction numerator fraction numerator straight m plus 4 straight n minus 5 straight l over denominator straight m minus straight l end fraction over denominator 2 end fraction open parentheses straight n plus straight l close parentheses
equals fraction numerator open parentheses straight n plus straight l close parentheses open parentheses straight m plus 4 straight n minus 5 straight l close parentheses over denominator 2 open parentheses straight m minus straight l close parentheses end fraction
straight k equals 2 end style
Answered by Expert 16th August 2018, 11:44 AM
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