Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

93219 24448 / 99871 78554

Mon to Sat - 10 AM to 7 PM

An object is projected horizontally from a top of the height h. The line joining the point of projection and point of striking on the ground  makes an angle 45° with ground, then with what velocity the object strikes  the ground

Asked by valavanvino1011 11th August 2018, 4:04 AM
Answered by Expert
Answer:
As shown in figure, if the projectile is making an angle 45º with horizontal,
then at the hitting point, its vertical component uv and horizontal component uh of velocity are equal because uv / uh = tan45
 
vertical componenet of velocity uv is the velocity gained in vertical direction by projectile while travelling
a vertical distance h,  which is equal to begin mathsize 12px style square root of 2 g h end root end style
hence velocity at point of striking the ground is begin mathsize 12px style square root of 2 g h space plus space 2 g h end root space equals space 2 square root of g h end root space m divided by s end style
Answered by Expert 11th August 2018, 8:04 AM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer 1/10

Your answer has been posted successfully!

Chat with us on WhatsApp