Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

9321924448

Mon to Sat - 10 AM to 7 PM

An engine pumps out water continuosly through a hose with a velocity v ,If miss the mass/unit length of water jet the rate at which K.E imparted is...?
A)1/2(mv^2)
B)1/2(mv^3)

Asked by mythili Suresh 21st September 2015, 1:51 PM
Answered by Expert
Answer:
begin mathsize 14px style The space rate space of space flowing space mass space is dm over dt equals dm over dx cross times dx over dt Now comma space straight m space is space the space mass space per space unit space length comma space straight i. straight e. comma space dm over dx equals straight m Hence comma space we space have comma space dm over dt equals straight m cross times dx over dt equals mv Therefore comma space the space rate space of space straight K. straight E space is dK over dt equals 1 half open parentheses dm over dt close parentheses straight v squared space space space space space left parenthesis For space constant space straight v right parenthesis space left square bracket straight K. straight E. equals 1 half mv squared right square bracket dK over dt equals 1 half open parentheses mv close parentheses squared equals 1 half mv cubed end style
Answered by Expert 21st September 2015, 6:20 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Free related questions

Chat with us on WhatsApp