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A uniform sphere of mass M and radius R exerts a force F on a small mass m situated at a distance of 2R from the centre O of the sphere. A spherical portion of diameter R is cut from the sphere as shown in the figure. The force of attraction between the remaining part of the sphere and the mass m is? 

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Asked by nasir.mirza 13th June 2018, 6:25 PM
Answered by Expert
Answer:
 
Let F1 be the gravitational force on a mass m placed at P, which is exerted by the grey colour mass as shown in figure .
 
Then we have  begin mathsize 12px style F space equals space G fraction numerator M space m over denominator 4 R squared end fraction space equals space F subscript 1 space plus space G fraction numerator open parentheses begin display style bevelled M over 8 end style close parentheses begin display style space end style begin display style m end style over denominator open parentheses begin display style bevelled 9 over 4 end style close parentheses begin display style R squared end style end fraction end style.......................(1)
where LHS of eqn.(1) is the gravitational force due to the full sphere and 2nd term of RHS is the gravitational force due to the removed sphere.
Proper mass of each sphere is considered.
By solving for F in equation (1), we get begin mathsize 12px style F subscript 1 space equals space 7 over 36 G fraction numerator M space m over denominator R squared end fraction space equals space 7 over 9 F end style
Answered by Expert 14th June 2018, 5:21 PM
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