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a saturated solution of salt has been prepared at 298K . on completely evaporating 35 gram of solution 10g of salt was recovered . calulate the amount of salt that was dissolved in 100g of water while preparing the solution. what is the solubililty of salt at 298K

Asked by Himanshi.kamra.06 8th September 2018, 8:48 PM
Answered by Expert
Answer:
First, find the concentration of the solution,
 
straight g space salt space present space in space 100 straight g space solution space will space be
space C o n c e n t r a t i o n space o f space s o l u t i o n equals fraction numerator 10 straight g over denominator 35 straight g end fraction cross times space 100 straight g space equals space 28.5714 space straight g space s a l t space
 
Let's find the weight of water,
 
100 minus 28.57 space equals space 71.43 space straight g space of space water space

This space suggests space that space there space is space 28.57 space straight g space salt space in space 71.43 space straight g space water
 
Let's calulate the solubility of salt at 298K
 
equals space fraction numerator 28.57 over denominator 71.43 end fraction cross times 100 space equals space 39.99 space almost equal to space 40 space straight g space salt
 
Answered by Expert 10th September 2018, 11:46 AM
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