- A moving particle of mass m has noe dimensional potential energy U(x)=a*x^2 + b*x^2, where a and b are poisitve constants.The angular frequency of small oscillations about minima of the potential energy is equal to:
Asked by saraswatmajumder
16th March 2018,
12:27 AM
Answered by Expert
Answer:
Potential energy U(x) = (a+b)×x2 = (1/2)×k×x2
k = 2(a+b) = ω2×m ;
hence angular frequency 
Answered by Expert
16th March 2018,
12:51 PM
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