A hiker stands on the edge of the cliff 490m above the ground and throws a stone horizontally with an initial speed of 15ms-1 neglecting air resistance. The time taken by the stone to reach the ground in s is (take g=9.8ms-2)
Asked by valavanvino1011
12th August 2018,
5:17 PM
Answered by Expert
Answer:
time taken by the stone to reach the ground is calculated using the formula " S = (1/2)gt2 "
because intial velocity component in vertical direction is zero.
where S is vertical distance 490 m and t is time.
490 = (1/2)×9.8×t2 , we get t = 10 s
Answered by Expert
12th August 2018,
5:40 PM
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