a capillary tube of 1 mm is dipped vertically in water. calculate the surface tension of water if the water rises 2.94cm above the outer level.density of water=100kg/m^3
Asked by Shabnakp
12th January 2013,
10:56 PM
Answered by Expert
Answer:
Radius of the narrow tube, r = 1 mm = 1 103 m
Density of water, ? =1000 kg/m3
Density of water, ? =1000 kg/m3
Acceleration due to gravity, g = 9.8 m/s2
Contact angle of water =00
Contact angle of water =00
Surface tension, S =hrg?/2
= 2.94 x 10-2 x 1 x 10-3 x 9.8 x 1000/2
=14.406 x 10-2N/m
Answered by Expert
13th January 2013,
12:08 AM
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