A body of mass 400g slides on a rough horizontal surface if the frictional force is 3.0N the angle made by the contact force on the body with the vertical will be
Asked by kanakpandeyyy
18th August 2018,
6:05 PM
Answered by Expert
Answer:
Figure shows the forces acting on the body. Contact forces are Normal reaction force N and friction force μN.
Resultant of these two contact forces are shown as R. Let R makes an angle θ with vertical as shown in figure.
then tanθ = μN / (mg) = μ ............(1)
In eqn.(1) we used the condition N = mg
hence the tangent of required angle is friction coefficient.
we are given that friction force 3 N and mass of the body 400 gram.
hence μN = μ×m×g = μ×0.4×9.8 = 3 ...........(2)
we get μ = 0.765 and tan-1μ = 37º
Answered by Expert
19th August 2018,
3:38 PM
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