.
Asked by sakshisingh3124
6th May 2018,
2:15 PM
Answered by Expert
Answer:
f(x) = ax2 + bx + 6 = 0
Accorrding to the question
Either f(x) ≥ 0 if a > 0
Or f(x) ≤ 0 if a < 0
f(0) = 6 > 0- hence a > 0
f(3) = 9a + 3b + 6 ≥ 0
3(3a + b) + 6 ≥ 0
3(3a + b) ≥ -6
3a + b ≥ -2
Hence, minimum value of 3a + b is -2.
Answered by Expert
7th May 2018,
12:52 PM
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