Work done by restoring force in a wire within elastic limit is -10J. Maximum amount of heat produced in the wire is - a) 10J, b) 20J, c) 5J, d) 15J
Asked by patra04011965
29th November 2018,
11:22 AM
Answered by Expert
Answer:
AS per thermodynamics law, ΔQ = ΔU+ΔW ....................(1)
where ΔQ heat energy absorbed/released, ΔU is change in internal energy and ΔW is workdone
Restoring force acts so quickly, there will be negligible heat loss. Hence we approximate this process as adiabatic and ΔQ = 0;
hence we have , ΔU+ΔW = 0, since ΔW= -10 J, we have ΔU = 10 J
Answered by Expert
30th November 2018,
5:23 AM
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