When x molecules are removed from 200mg of n2o , 2,89*10 moles are Left x will be
Asked by sanjaygoliyan
13th July 2018,
11:28 AM
Answered by Expert
Answer:
Molecular mass of N2O =44g
Weight of N2O = 200 mg = 0.2 g
Moles of N2O present = 0.22/44 = 4.55 × 10-3
Let moles of N2O removed be = x
Moles of N2O left = 2.89 × 10-3
Thus, 4.55 × 10-3 - x = 2.89 × 10-3
→ x= 4.55 × 10-3 - 2.89 × 10-3
x= 1.66 × 10-3 moles
No. of moles in 1 mole = 6.022× 1023
No. of x moles = x × 6.022× 1023
= 1.66 × 10-3× 6.022× 1023 moles
x = 9.97× 1020moles
Answered by Expert
27th July 2018,
12:27 PM
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