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Home / Doubts and Solutions/JEE/Physics

velocity-time equation of a particle moving in a straight line is v=(3tsqure+2t+10) find (a) displacement of a particle from the origin ot time t=1s if it is given that displacement is 20 m at time t=0

(b) acceralation time equation

Asked by gargpuneet989 25th June 2018, 8:58 AM
Answered by Expert
Answer:
begin mathsize 12px style v space equals space fraction numerator d x over denominator d t end fraction space equals space 3 t squared plus 2 t space plus 10 space......... left parenthesis 1 right parenthesis i f space w e space i n t e g r a t e space e q n. left parenthesis 1 right parenthesis comma space w e space g e t space comma space space x space equals space t cubed plus t squared plus 10 t plus C space.......... left parenthesis 2 right parenthesis w h e r e space C space i s space c o n s tan t space o f space i n t e g r a t i o n comma space w h i c h space i s space t o space b e space e v a l u a t e d space u sin g space t h e space g i v e n space c o n d i t i o n space comma space a t space t equals 0 comma space x equals 20. space space w e space g e t space C space equals space 20 H e n c e space comma space space space x space equals space space t cubed plus t squared plus 10 t plus 20 space........... left parenthesis 3 right parenthesis d i s p l a c e m e n t space a t space t equals 1 comma space space x space equals space 1 plus 1 plus 10 plus 20 space equals space 32 space a c c e l e r a t i o n space i s space o b t a i n e d space b y space d i f f e r e n t i a t i n g space e q n. left parenthesis 1 right parenthesis fraction numerator d v over denominator d t end fraction equals space 6 t plus 2 end style
Answered by Expert 25th June 2018, 9:50 AM
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