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Home / Doubts and Solutions/NEET/Physics

two springs have their respective force constants k1 and k2. both are streached till their elastic potential energies are equal.if the stretching forces are f1 and f2 find f1/f2

Asked by Mahima 27th June 2018, 7:26 PM
Answered by Expert
Answer:
Let, for same potential energy, elongations of springs be x1 and x2 and their respective force constants be k1 and k2.
 
then we have,  
 
begin mathsize 12px style 1 half k subscript 1 x subscript 1 superscript 2 space equals space fraction numerator begin display style 1 end style over denominator begin display style 2 end style end fraction k subscript 2 x subscript 2 superscript 2 space space space space h e n c e space fraction numerator x subscript 1 superscript 2 over denominator x subscript 2 superscript 2 end fraction space equals space k subscript 2 over k subscript 1 space.................... left parenthesis 1 right parenthesis end style
 
using eqn.(1), we can write that, begin mathsize 12px style f subscript 1 over f subscript 2 space equals space fraction numerator k subscript 1 x subscript 1 over denominator k subscript 2 x subscript 2 end fraction space equals space k subscript 1 over k subscript 2 space cross times square root of k subscript 2 over k subscript 1 end root space equals space square root of fraction numerator begin display style k subscript 1 end style over denominator begin display style k subscript 2 end style end fraction end root space end style
Answered by Expert 28th June 2018, 10:50 AM
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