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Two concentric circular coils is having 10 turns with radius 0.2 metre and 0.4 metre carrying current 0.2 ampere and 0.3 ampere respectively in opposite direction in the magnetic field at the centre is

Asked by hemanttkumarr 23rd May 2018, 9:53 PM
Answered by Expert
Answer:
Magnetic field in the circular coil is given by,
B equals space fraction numerator mu subscript 0 N I over denominator 2 R end fraction
w h e r e comma space B minus space m a g n e t i c space f i e l d space
N space minus space n u m b e r space o f space t u r n s
I minus space c u r r e n t space
R minus space R a d i u s space o f space c o i l

A s space t h e space c u r r e n t space i s space f l o w i n g space t h r o u g h space t w o space c o n c e n t r i c space l o o p s space i n space o p p o s i t e space d i r e c t i o n
B equals fraction numerator begin display style mu subscript 0 left parenthesis 10 right parenthesis end style over denominator begin display style 2 end style end fraction open parentheses fraction numerator 0.2 over denominator 0.2 end fraction minus fraction numerator 0.3 over denominator 0.4 end fraction close parentheses space
B equals mu subscript 0 cross times 5 cross times open parentheses fraction numerator 0.2 over denominator 0.2 end fraction minus fraction numerator 0.3 over denominator 0.4 end fraction close parentheses space equals 5 over 4 mu subscript 0 space T e s l a space equals space 1.25 mu subscript 0 space T e s l a space space left parenthesis mu subscript 0 equals space 4 pi cross times 10 to the power of negative 7 end exponent space H right parenthesis
Hence, magnetic field at the centre is 5 over 4 mu subscript 0 space T e s l a space o r space 1.25 mu subscript 0 space T e s l a
Answered by Expert 24th May 2018, 11:22 AM
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