Two blocks A and B are connected by a massless string .A force of 30N is applied on block B.The distance travelled by centre of mass in 2s starting from rest is
Asked by m.nilu
12th September 2018,
7:40 PM
Answered by Expert
Answer:
acceleration a of the system = 30/(mA+mB) m/s2 .
where mA and mB are mass of block-A and block-B respectively.
Centre of mass also moves with this acceleration.
distance S moved after 4 sec = (1/2)×a×t2 = (1/2)× [ 30 / (mA+mB) ] × 4 = [ 60 / (mA+mB) ] m
Answered by Expert
14th September 2018,
3:14 PM
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