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Home / Doubts and Solutions/NEET/Physics

Three charges +27 ,-125 ,+64 esu are situated at the corners A,B,C respectively of a rectangle ABCD having sides ABCD having sides AB =8 cm & BC =6 cm . Find the force on charge +5 esu placed at D. Find also the potential at D. 

Asked by mridulabarua05 19th February 2019, 12:05 PM
Answered by Expert
Answer:
Units conversion : 1 esu = 3.336 C
 
Electrostatic force F at D = FA + FB + FC  = begin mathsize 12px style plus fraction numerator 5 cross times 27 cross times open parentheses 3.336 cross times 10 to the power of negative 10 end exponent close parentheses squared over denominator 6 cross times 6 cross times 10 to the power of negative 4 end exponent end fraction minus fraction numerator 5 cross times 125 cross times open parentheses 3.336 cross times 10 to the power of negative 10 end exponent close parentheses squared over denominator 10 cross times 10 cross times 10 to the power of negative 4 end exponent end fraction plus fraction numerator 5 cross times 64 cross times open parentheses 3.336 cross times 10 to the power of negative 10 end exponent close parentheses squared over denominator 8 cross times 8 cross times 10 to the power of negative 4 end exponent end fraction space end style  Newton
F = 27.82 × 10-16 N
 
Electrostatic potential V at D = VA + VB + VC = begin mathsize 12px style plus fraction numerator 5 cross times 27 cross times open parentheses 3.336 cross times 10 to the power of negative 10 end exponent close parentheses squared over denominator 6 cross times 10 to the power of negative 2 end exponent end fraction minus fraction numerator 5 cross times 125 cross times open parentheses 3.336 cross times 10 to the power of negative 10 end exponent close parentheses squared over denominator 10 cross times 10 to the power of negative 2 end exponent end fraction plus fraction numerator 5 cross times 64 cross times open parentheses 3.336 cross times 10 to the power of negative 10 end exponent close parentheses squared over denominator 8 cross times 10 to the power of negative 2 end exponent end fraction space end style Volt
V = 626×10-18 V
Answered by Expert 19th February 2019, 1:04 PM
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