Three blocks A,B,C of equal mass m are placed one over the other on a smooth horizontal ground as shown. Coefficient of friction bet any two blocks of A,B,C is 1/2. The max value of mass of block D so that the blocks A,B,C move without slipping over each other is
Asked by m.nilu
30th July 2018,
12:10 PM
Answered by Expert
Answer:
Tension T in the string pulls the combined system that consists of 3 masses.
If T is the tension in the string, then we get acceleration a = T/(3m)
Hence mass of block-A moves due to the net pulling force F= (m×a - μ×m×g) = ( (T/3) - μ×m×g)
The required condition for the block-A not to slip is, F ≤ 0
hence (T/3) ≤ (μ×m×g)
since T = mD ×g , we get mD ≤ 3×μ×m
Answered by Expert
31st July 2018,
1:07 PM
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