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THE VOLUME OF AN AIR BUBBLE BECOMES THREE TIMES AS IT RISES FROM THE BOTTOM OF A LAKE TO ITS SURFACE ,ASSUMING ATMOSPERIC PRESSURE TO BE 75CM OF Hg AND THE DENSITY OF DENSITY OF WATER TO BE 1/10 OF THE DENSITY OF MERCURY ,THE DEPTH OF LAKE?A-5Mm,b-10m,c-15m,d-20m

Asked by amitjena226 19th December 2017, 10:10 AM
Answered by Expert
Answer:
P1×3V = P0×V
begin mathsize 12px style open parentheses 75 rho g space plus space 1 over 10 rho g h close parentheses V space equals space 75 rho g cross times 3 V end style
solving for h, we will get h = 1500 cm = 1.5 m
Answered by Expert 19th December 2017, 11:36 AM
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