the self inductance of cooil having 400 turns is 10mH, the magnetic flux through the cross section of the coil corresponding to current 2mH is?
Asked by imtiyazmulla68
23rd March 2018,
9:35 PM
Answered by Expert
Answer:
The required formula is L×i = N×Φ , where L is the self-inductance, i is current , N is number of turns and Φ is magnetic flux,
you are given with L, i and N. hence find Φ using the above formula
Answered by Expert
24th March 2018,
7:31 AM
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