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The radioactivity of an old sample of a liquid due to tritium half life 12.5years was found to be only about 3% of that measured in a recently purchased bottle marked 7years old .the sample must have been prepared about

Asked by sudheerkapoor67 15th October 2017, 9:25 PM
Answered by Expert
Answer:
Radioactivity relation is given by N space equals space N subscript 0 e x p left parenthesis negative lambda t right parenthesis 
As given in the problem N/N0 = 0.03 and λ = ln2/T1/2 
 
Hence  N over N subscript 0 space equals space 0.03 space equals space e x p left parenthesis negative lambda t right parenthesis space

ln left parenthesis 0.03 right parenthesis space equals space minus lambda t space equals space fraction numerator negative ln left parenthesis 2 right parenthesis cross times t over denominator T subscript 1 divided by 2 end subscript end fraction

t space equals space fraction numerator ln left parenthesis 0.03 right parenthesis space cross times space T subscript 1 divided by 2 end subscript over denominator negative ln left parenthesis 2 right parenthesis end fraction space equals space 63 space.24 space y e a r s
Answered by Expert 16th October 2017, 12:18 PM
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