The mole fraction of glucose in aqueous solution is 0.2,then molality of solution will be
Asked by 2045820269079977
8th May 2018,
9:48 AM
Answered by Expert
Answer:
Given:
Mole fraction of glucose= 0.2
Molefraction of solution = 1
So, mole fraction of water= 1-0.2
= 0.8
Molality = moles of solute/ kg solvent
Molar mass H2O = 18 g/kg
Mass of H2O = (0.8×18)/1000
=0.014 kg
Molality = 0.2 / 0.014
= 14 M
Answered by Expert
8th May 2018,
10:57 AM
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