The molar enthalpy of vaporization of benzene at its boiling pt (353K) is 30.84kJ/mol.What is the molar internal energy change?For how long would a 12 volt source need to supply a 0.5A current in order to vaporize 7.8g of the sample at its boiling pt.?
Asked by m.nilu
23rd September 2018,
11:02 PM
Answered by Expert
Answer:
C6H6 (l) ---------> C6H6 (g)
here, change in gaseous mole = 1 mol.
Now, dH = dE + dn R T
30840 = dE + (1 * 8.314 * 353 )
dE = 27905.158 joule
= 27.905 kJ (ans)
Now, mole for 7.8g benzene = 7.8/78 = 0.1 mol.
so, energy needed for evaporate 0.1 mol benzene = 30.84 * 0.1 = 3.084 kJ = 3084 J.
Now, energy = V * I * t
3084 = 12 * 0.5 * t
So, t = 514 second (ans)
Answered by Expert
4th October 2018,
9:11 PM
Rate this answer
- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
You have rated this answer /10
Your answer has been posted successfully!
RELATED STUDY RESOURCES :
Browse free questions and answers by Chapters
- 1 Classification of Elements and Periodicity in Properties
- 2 Chemical Bonding and Molecular Structure
- 3 States of Matter
- 4 Equilibrium
- 5 Hydrogen
- 6 Hydrocarbons
- 7 Environmental Chemistry
- 8 Solutions
- 9 Chemical Kinetics
- 10 Surface Chemistry
- 11 Biomolecules
- 12 Polymers
- 13 Chemistry in Everyday Life
- 14 Atomic Structure
- 15 Chemical Thermodynamics
- 16 Redox Reactions and Electrochemistry
- 17 p-Block Elements
- 18 d - and f - Block Elements
- 19 Some Basic Principles of Organic Chemistry
- 20 Organic Compounds Containing Halogens
- 21 Organic Compounds Containing Oxygen
- 22 Organic Compounds Containing Nitrogen
- 23 Co-ordination Compounds
- 24 Purification and Characterisation of Organic Compounds
- 25 s-Block Element (Alkali and Alkaline Earth Metals)
- 26 Solid State
- 27 Some Basic Concepts in Chemistry
- 28 General Principles and Processes of Isolation of Metals
- 29 Principles Related to Practical Chemistry
Trending Tags
Latest Questions
JEE Main Mathematics
Asked by amaladelsingh
28th October 2020,
10:24 PM
CBSE X Biology
Asked by reenacharan2008
28th October 2020,
9:11 PM
