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The fundamental frequency of a stretched string increases by 15 hz, when it's tension is increased by 144%. Now maintaining the initial tension in the wire if the length is increased by 40% what will be the change in the fundamental frequency ?

Asked by dipanshusingla029 23rd March 2018, 10:58 AM
Answered by Expert
Answer:
The equation relating frequency, wavelength , Tension in the string , mass density of string and length of string is given below
 
begin mathsize 12px style square root of T over mu end root space equals space n lambda space equals space n cross times 2 L end style
T is tension in the string, μ is mass density (mass/Length), n is frequency in Hz, λ is wavelength of fundamental and L is length of string.
 
Initially Tension is increased by 144% and frquency is 15 Hz. The original tension T is obtained as folows
 
begin mathsize 12px style square root of fraction numerator 2.44 cross times T cross times L over denominator m end fraction end root space equals space 15 cross times 2 L space semicolon space m space i s space m a s s space o f space s t r i n g

l e t space u s space g e t space T space i n space t e r m s space o f space m space a n d space L semicolon space F space equals space 369 space L cross times m

end style
now frequency with original tension and 40% increase in wavelength is given by
begin mathsize 12px style square root of fraction numerator 369 L cross times m cross times 1.4 L over denominator m end fraction end root space equals space n cross times 2 cross times left parenthesis 1.4 L right parenthesis
end style
we get the frequency n = 8 Hz.
Answered by Expert 23rd March 2018, 12:01 PM
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