the father's age 10years ago was 35 years more than twice his son's age after how many years from now will the father be twice his son age
Asked by shiv ganesh
23rd May 2012,
3:44 PM
Answered by Expert
Answer:
Let father's and son's age, 10 years ago, be f and s respectively.
From the given information,
f = 2s + 35 ... (i)
Present age of father = f + 10
Present age of son = s + 10
Let after x number of years, father be twice his son's age. Then, we have:
f + 10 + x = 2(s + 10 + x)
On simplifying, we get, x = f - 2s - 10
Using (i), we get,
x = 35 - 10 = 25
Thus, after 25 years father will be twice his son's age.
Answered by Expert
23rd May 2012,
10:51 PM
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