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Home / Doubts and Solutions/NEET-BASIC/Neet/Chemistry

the available nitrogen in 100 kj urea samle is found to be 35% by weight. the actual urea content in sample  will be?

Asked by imtiyazmulla68 19th November 2017, 7:32 PM
Answered by Expert
Answer:
Molecular space weight space of space urea space equals space 60 35 percent sign space nitrogen space by space weight comma 60 cross times 35 over 100 equals 21 Actual space urea space content equals 60 minus 21 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 39 For space 100 space kg space urea fraction numerator 100 cross times 10 cubed space straight g cross times 39 over denominator 60 end fraction space equals space 6.55 cross times 10 to the power of 4 space straight g space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 65.5 space kg
Answered by Expert 20th November 2017, 4:11 PM
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