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Suppose AB and CD are two perpendicular
chords of the same circle that intersect at the point
E,AE = 12, DE = 4 and CE = 6. The area of the
circle, is 

Asked by sourabh 24th March 2015, 12:05 PM
Answered by Expert
Answer:

Refer to the above figure.

In triangle OFA , 12+x2=r2

In triangle OGC, (12-x)2+52=r2

Hence, (12-x)2+52=12+x2

Solving we get x=7.

Hence, 12+72=r2=50

Area of the circle is πr squared equals 50 straight pi

Answered by Expert 24th March 2015, 7:00 PM
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