Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

93219 24448 / 89292 63204

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

81783 72169
OR

Chat with us on WhatsApp

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

93219 24448 / 99871 78554

Mon to Sat - 10 AM to 7 PM

Home / Doubts and Solutions/JEE/Physics

Solve it

qsnImg
Asked by venkat 14th May 2018, 6:58 PM
Answered by Expert
Answer:
To just lift a plate of area density 2 kg/m2, the required force per area F is given by
 
F = 2×9.8 = 19.6 kg/m2 ...........................(1)
 
We need to find charge density on a plate to lift another body using this charge density.
Hence the problem is considering the force between parallel plates of capactor.
 
Force between parallel plate Fc is given by
where Q is charge in Coulomb, A is area of plates, ε0 is the permeability.
Since we need Force per unit area we need to divivide eqn.(2) by area A
Hence Force per Area is given as
By equating (1) and (3) , we get charge density σ as
Answered by Expert 15th May 2018, 12:30 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Report an issue
Tags: charge
Previous Question
Next Question
Your answer has been posted successfully!

Free related questions

If charge on one electron is 1.6 x 10 -19 C. Calculate number of electrons required to constitute 1A of current in 1s.
28th December 2021, 7:46 PM
Define charge density.
12th January 2022, 2:00 PM
A conductor carries a current of 0.2 A. [3] i) Find the amount of charge that will pass through the cross section of conductor in 40 s. ii) How many electrons will flow in this time interval if charge on one electron is 1.6 x 10–19 C ?
8th February 2022, 11:31 AM
An oil drop of mass 3.25*10^(-15) kg falls vertically with uniform velocity , through the air between vertical parallel plates which are 2 m apart. When a p.d. of 1000 V is applied to the plates the drop moves to the positively charged plate , being inclined at 45 degrees to the vertical. Calculate the charge on the drop. 
15th March 2022, 2:35 PM
ln a Millikan’s oil drop experiment, the horizontal plates are 1.5 cm apart. With the electric field switch off an oil drop is observed to fall with a steady velocity of 2.5×10^{-2}  cm  s^{-1}.  When the field is switched on the upper plate being positive, the drop just remains stationary when the   p.d.   between the plates is 1500 V. Calculate the radius of drop (b) How many electronic charges does it carry? (c)If the   p.d. between the two plates remains unchanged, with what velocity will the drop move when it has collected two more as a result of exposure to ionising radiation? (Oil density, rho=900 kgm^{3} , Viscosity of air,   eta =1.8×10^{-5} Nsm^{-2}, Density of air,  σ=1.293  kg  m^{-3})
1st April 2022, 9:44 AM
RELATED STUDY RESOURCES :
JEE QUESTION ANSWERS

Browse free questions and answers by Chapters

Trending Tags

trigonometric equations Mole concept linear equations functions electric force trigonometric ratios circle quadratic equation matrix operations magnetic field

Latest Questions

CBSE X Biology
What is enzyme  
Asked by Sureshgowdayd548 28th October 2020, 10:50 PM
JEE Main Mathematics
The following pseudocode is executed using the “Paragraph words” dataset. At the end of the execution, CountB captures the number of verbs with letter count less than the average letter count of verbs. But the pseudocode may have mistakes in one or more lines. Identify all such lines (if any). It is a Multiple Select Question (MSQ).  Error in Line 4  Error in Line 8  Error in Line 11  Error at Line 12  Error in Line 17  Error at Line 18  Error in Line 21 The following pseudocode is executed using the “Words” table. What will be the value of A at the end of the execution?
Asked by amaladelsingh 28th October 2020, 10:24 PM
CBSE X Biology
I want a brief clarity on Taxonomy
Asked by reenacharan2008 28th October 2020, 9:11 PM

Chat with us on WhatsApp