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Question attached as single question as instructed by you - i.e question no-9 only

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Asked by shobhit 5th April 2018, 8:08 AM
Answered by Expert
Answer:
mean free path l is given by begin mathsize 12px style l space equals space fraction numerator 1 over denominator square root of 2 n pi d squared end fraction end style...................(1)
n = number density = 1000×106 /cm3  = 1000×106×106 /m3 = 1015 /m3
d = moleculer diameter = 2 × 10-10 m
Substitue these numbers in (1) to get mean free path. I got the answer as 5.63 km
Answered by Expert 5th April 2018, 1:05 PM
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