Sir pls solve this question.
Asked by rsudipto
11th December 2018,
9:30 AM
Answered by Expert
Answer:
Given:
Surface area = 80 cm2
Density = 10.5 g cm-3
Current = 3A
Thickness = 5 ×10-3cm
Mass of the silver deposited will be (m) = Area × Thickness × density = 80 × 5 ×10-3 × 10.5 = 4.2 g
As we know,
E = Z × 96500
Z = 
g
gNow, lets current passed through for t sec.
Answered by Expert
11th December 2018,
11:48 AM
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