Sir
Pl solve
Question no-11 attached
Asked by shobhit
14th May 2018,
9:01 AM
Answered by Expert
Answer:
Figure describes the question. Let the distance of P from O, i.e. OP is S. Then we have
S = 3×tanθ ......(1)
differentiate (1), then we have (dS/dt) = 3×sec2θ×(dθ/dt) ............(2)
when θ=45º , and by substituting (dθ/dt) = 0.1 rad/s, we get the speed of spot P using eqn.(2) as given below
(dS/dt) = 3 × (√2)2 × (0.1) = 0.6 m/s
Answered by Expert
14th May 2018,
3:09 PM
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