Show that x=3, y=1 is a solution of the equation 3x-2y=7.
Substitute x = 3 and y = 1 in 3x-2y=7.
L.H.S = 3x - 2y = 3(3) - 2(1) = 9 - 2 = 7 = R.H.S
→ x = 3 and y = 1 is the solution of 3x-2y=7.
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Show that x=3, y=1 is a solution of the equation 3x-2y=7.
Substitute x = 3 and y = 1 in 3x-2y=7.
L.H.S = 3x - 2y = 3(3) - 2(1) = 9 - 2 = 7 = R.H.S
→ x = 3 and y = 1 is the solution of 3x-2y=7.
You have rated this answer /10