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Home / Doubts and Solutions/JEE/Physics

Question

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Asked by rbhatt16 26th June 2018, 6:12 PM
Answered by Expert
Answer:
Let ν1 be the frequency when the tuning fork moving away from the stationary observer. 
 
begin mathsize 12px style nu subscript 1 space equals space nu subscript 0 open parentheses 1 minus v subscript s over v close parentheses space............ left parenthesis 1 right parenthesis end style 
where vs and v are velocity of source and that of sound respectively. ν0 is the frequency of tuning fork.
 
Let ν2 be the frequency when the tuning fork moving towards stationary observer. 
 
begin mathsize 12px style nu subscript 2 space equals space nu subscript 0 open parentheses 1 plus v subscript s over v close parentheses space............ left parenthesis 2 right parenthesis end style 
Beat frequency  is given by, begin mathsize 12px style nu subscript 2 minus nu subscript 1 space equals space 2 nu subscript 0 nu subscript S over v space equals space 2 space H z space................ left parenthesis 3 right parenthesis end style
hence begin mathsize 12px style v subscript S space equals space v over nu subscript 0 space space equals space 340 over 680 space equals space 0.5 space m divided by s end style
Answered by Expert 27th June 2018, 11:23 AM
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