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ques 6 and ques 7

Asked by rbhatt16 12th October 2017, 4:58 PM
Answered by Expert
Answer:
Question 6
 
The distance S and plane height h are related by tan theta space equals space h over S space equals space 8000 over S
Hence S space equals space 8000 space c o t theta 
 
if we diferentiate the above equation fraction numerator d S over denominator d t end fraction space equals space minus 8000 space cos e c squared theta space fraction numerator d theta over denominator d t end fraction
 
fraction numerator d S over denominator d t end fraction is speed of plane and fraction numerator d theta over denominator d t end fraction = 0.025 rad/s (given)
 
hence speed of plane fraction numerator d S over denominator d t end fraction space equals space minus 8000 cross times fraction numerator 1 over denominator begin display style sin squared end style begin display style theta end style end fraction space x space fraction numerator d theta over denominator d t end fraction space equals space minus 8000 space cross times space 4 over 3 space cross times left parenthesis negative 0.025 right parenthesis space equals space 267 space m divided by s
 
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Question 7
 
Total acceleration square root of a subscript r superscript 2 plus a subscript t superscript 2 space end root space equals space 100, where ar is radial acceleration and at is tangential accelerartion 
Hence a subscript r superscript 2 space plus space a subscript t superscript 2 space equals space 100 squared 
a subscript r superscript 2 space equals space 100 squared space minus space a subscript t superscript 2 space equals space 100 squared minus space 60 squared space equals space 160 cross times 40
a subscript r equals space 80 space m divided by s squared
since a subscript r space equals space v squared over r where r is radius, then r space equals space v squared over a subscript r space equals space fraction numerator 10 cross times 10 over denominator 80 end fraction space equals space 1.25 space m

Answered by Expert 13th October 2017, 3:10 PM
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