ques 5
ques 5
Asked by rbhatt16
10th November 2017,
3:17 PM
Answered by Expert
Answer:
The displacement of the edge of the arm AB is dependent on the angular displacement of the arm OA.
the rate at which arm OA rotates (dθ/dt) is proportional to the rate at which arm AB undergoes linear motion with velocity "ds/dt"
Therefore
s=lxcosθ
ds/dt =l x cosθ xdθ/dt
is the velocity of the edge of the arm.
Answered by Expert
6th December 2017,
4:05 PM
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