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Home / Doubts and Solutions/GUJARAT - GUJARATI MEDIUM/Class 9/ગણિત

QID : 61 - In an army selection process, the ratio of selected to unselected candidates was 9:2. If 80 less had applied and 20 less selected, the ratio of selected to
unselected would have been 5:1. How many candidates had applied for the process?

Asked by aryap7964 6th December 2017, 4:54 PM
Answered by Expert
Answer:
begin mathsize 16px style Let space the space ratio space of space selected space to space unselected space candidates space equals straight x over straight y equals fraction numerator 9 straight m over denominator 2 straight m end fraction Then comma space the space total space number space of space candidates equals 9 straight m plus 2 straight m equals 11 straight m Also space given space that space 80 space less space had space applied space and space 20 space less space selected comma space the space ratio space of space selected space to space unselected space would space have space been space 5 space colon space 1 rightwards double arrow 11 straight m space minus space 80 space have space been space applied space and space 9 straight m space minus space 20 space has space selected comma space space Total space number space of space unselected space candidates equals Total space number space of space applied space candidates space – space Total space number space of space selected space candidates equals left parenthesis 11 straight m space – space 80 right parenthesis space – space left parenthesis 9 straight m space – space 20 right parenthesis equals space 2 straight m space minus space 60 Now comma fraction numerator Selected space candidates over denominator Unselected space candidates end fraction equals 5 over 1 rightwards double arrow fraction numerator 9 straight m minus 20 over denominator 2 straight m minus 60 end fraction equals 5 over 1 rightwards double arrow 9 straight m space minus space 20 space equals 10 straight m minus 300 rightwards double arrow straight m equals 280 rightwards double arrow Total space number space of space candidates equals 11 straight m equals 11 cross times 280 equals 3080 end style
Answered by Expert 8th December 2017, 12:18 PM
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