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Home / Doubts and Solutions/JEE/Physics

Q7 pls

Asked by Tanishq 14th October 2017, 6:37 AM
Answered by Expert
Answer:
The condition required for the bead to not slip is 

begin mathsize 12px style uN equals space mω squared straight L Normal space force space can space be space given space as space straight N equals ma equals straight m left parenthesis αL right parenthesis straight a equals space linear space acceleration therefore space the space maximum space frictional space force space on space bead space can space be space given space as straight F equals uN equals straight u left parenthesis mαL right parenthesis the space limiting space case space for space the space bead space to space not space slip space is straight u space straight x space straight m space straight x space straight alpha space straight x space straight L space greater or equal than space space mω squared straight L therefore space it space will space just space slip space when space straight omega squared equals straight u space straight x space straight alpha space and space straight omega equals αxt straight t equals straight omega over straight alpha equals fraction numerator square root of uxα over denominator straight alpha end fraction equals square root of straight u over straight alpha end root end style
Answered by Expert 29th November 2017, 3:15 PM
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