Q) Please explain the solution of this problem
From Raoult’s law for a non-volatile solute like urea,
Ps/Po = X1
22.98/23.75 =X1= 0.9675
Mole fraction of H2O = 0.9875
Mole fraction of urea= (1- 0.9875)
=0.0324
Molality = No. of moles of urea/Mass of water in kg = (0.0324/ (0.9875x18) x 1000 = 1.82m
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