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potassium crystallizes in  abody centred cubic unit lattice. How many unit cells are present in 2g potassium? 
 
(I have the solution for this I just want the explanation of procedure)

Asked by pratuchav.0 1st May 2015, 12:13 PM
Answered by Expert
Answer:

Dear Pratiksha,

1 mole of K = 39.1 g = 6.02 x 1023 formula units.

Hence, No. of formula units in 2 g of K = 6.02 x 1023 x 2 / 39.1

As one unit cell of K contains 2 K formula units, therefore, number of unit cells present in 2 g of K = 6.02 x 1023 x 2 / 39.1 x 2 = 0.154 x 1023 unit cells

Answered by Expert 4th May 2015, 6:16 PM
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