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Home / Doubts and Solutions/NEET/Physical Chemistry I

Plz solve in paper

Asked by ashutosh25807 18th October 2017, 10:47 AM
Answered by Expert
Answer:
For H-like particles, the formula is
 
nu equals R open parentheses 1 over n subscript 1 squared minus 1 over n subscript 2 squared close parentheses Z squared F o r space B e comma space Z equals 4 space space equals 1.097 cross times 10 to the power of 7 to the power of blank end exponent m to the power of negative 1 end exponent open parentheses 1 over 1 squared minus 1 over 2 squared close parentheses open parentheses 4 squared close parentheses space space equals 1.097 cross times 10 to the power of 7 to the power of blank end exponent m to the power of negative 1 end exponent open parentheses fraction numerator 4 minus 1 over denominator 4 end fraction close parentheses 16 space space equals 1.097 cross times 10 to the power of 7 to the power of blank end exponent m to the power of negative 1 end exponent open parentheses 3 over 4 close parentheses 16 space space equals 1.097 cross times 10 to the power of 7 to the power of blank end exponent m to the power of negative 1 end exponent open parentheses 12 close parentheses nu space equals 13.164 cross times 10 to the power of 7 space m to the power of negative 1 end exponent end exponent lambda equals 1 over nu space space equals fraction numerator 1 over denominator 13.164 cross times 10 to the power of 7 space m to the power of negative 1 end exponent end exponent end fraction space space lambda space space equals 7.59 cross times 10 to the power of negative 9 end exponent space m E space equals fraction numerator h c over denominator lambda end fraction space space space space equals fraction numerator 6.63 cross times 10 to the power of negative 34 end exponent cross times open parentheses 3 cross times 10 to the power of 8 close parentheses over denominator 7.59 cross times 10 to the power of negative 9 end exponent end fraction space space space space equals space 261.7 cross times 10 to the power of negative 19 end exponent space space J space space space space space equals space 261.7 cross times 10 to the power of negative 19 end exponent cross times 6.2415 cross times 10 to the power of 18 space space space space equals 163.2 space e V
 
   = 
Answered by Expert 20th October 2017, 11:21 AM
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