Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

93219 24448 / 99871 78554

Mon to Sat - 10 AM to 7 PM

Pls solve 

qsnImg
Asked by g_archanasharma 24th March 2018, 5:29 PM
Answered by Expert
Answer:
Let us assume the detector has moved a distance y cm from the centre.
Path difference d2-d1 is calculated as follows
begin mathsize 12px style d subscript 1 superscript 2 equals 24 squared plus open parentheses 1.5 minus y close parentheses squared d subscript 2 superscript 2 equals 24 squared plus open parentheses 1.5 plus y close parentheses squared d subscript 2 superscript 2 minus d subscript 1 superscript 2 space equals space 6 cross times y open parentheses d subscript 2 minus d subscript 1 close parentheses cross times 2 d space equals space 6 cross times y semicolon space w e space h a v e space a s s u m e d space left parenthesis d subscript 2 plus d subscript 1 right parenthesis space almost equal to 2 d space left parenthesis d subscript 2 minus d subscript 1 right parenthesis cross times 2 square root of 24 squared plus 1.5 squared end root space equals space 48.1 cross times left parenthesis d subscript 2 minus d subscript 1 right parenthesis space equals space 6 cross times y end style
 
for destructive interfrence (d2-d1) should be λ/2; since λ = 2 cm, we have (d2-d1) = 1 cm; 
 
hence y = 48.1/6 = 8 cm
Answered by Expert 25th March 2018, 6:03 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Tags: sound-waves
Your answer has been posted successfully!

Free related questions

31st March 2022, 10:39 AM
8th January 2023, 11:34 AM
12th January 2023, 8:57 PM

Chat with us on WhatsApp