Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

93219 24448 / 99871 78554

Mon to Sat - 10 AM to 7 PM

Please solve this problem

 

qsnImg
Asked by aadeshsatpute375 27th July 2018, 8:19 PM
Answered by Expert
Answer:
Angular speed ω begin mathsize 12px style equals space fraction numerator A n g u l a r space d i s p l a c e m e n t over denominator t i m e end fraction space equals space fraction numerator 7 cross times 2 pi cross times 12 cross times 10 to the power of negative 2 end exponent over denominator 100 end fraction equals 0.0528 space r a d divided by s end style
linear speed v = ω×r = 0.0528×12×10-2 = 6.33×10-3 m/s
 
acceleration vector is constant and is directed towards centre of circle.
 
magnitude of acceleration vector begin mathsize 12px style v squared over r space equals space fraction numerator begin display style open parentheses 6.33 cross times 10 to the power of negative 3 end exponent close parentheses squared end style over denominator 12 cross times 10 to the power of negative 2 end exponent end fraction space equals space 3.34 cross times 10 to the power of negative 4 end exponent m divided by s squared end style
Answered by Expert 29th July 2018, 11:28 AM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp