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Please solve this problem

 

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Asked by aadeshsatpute375 27th July 2018, 8:19 PM
Answered by Expert
Answer:
Angular speed ω begin mathsize 12px style equals space fraction numerator A n g u l a r space d i s p l a c e m e n t over denominator t i m e end fraction space equals space fraction numerator 7 cross times 2 pi cross times 12 cross times 10 to the power of negative 2 end exponent over denominator 100 end fraction equals 0.0528 space r a d divided by s end style
linear speed v = ω×r = 0.0528×12×10-2 = 6.33×10-3 m/s
 
acceleration vector is constant and is directed towards centre of circle.
 
magnitude of acceleration vector begin mathsize 12px style v squared over r space equals space fraction numerator begin display style open parentheses 6.33 cross times 10 to the power of negative 3 end exponent close parentheses squared end style over denominator 12 cross times 10 to the power of negative 2 end exponent end fraction space equals space 3.34 cross times 10 to the power of negative 4 end exponent m divided by s squared end style
Answered by Expert 29th July 2018, 11:28 AM
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