please solve and explain the soln
Asked by jaychandran1967
21st November 2018,
4:38 PM
Answered by Expert
Answer:
we know from first law of thermodynamics, ΔU = ΔQ - ΔW...........(1)
where ΔU is the internal energy of the system, ΔQ is the heat energy absorbed/released and ΔW is workdone.
Since the moving gas is suddenly stopped, it is adiabatic process, hence ΔQ = 0.
hence ΔU = - ΔW .............(2)
we have ΔU = n×CV ×ΔT , where n is number of moles, CV is specific heat and ΔT is rise in temperature.
hence n×CV ×ΔT = (1/2)mv2
Let M0 be moleculer weight and v is speed of gas
(m/M0)×CV ×ΔT = (1/2)mv2 or 
Answered by Expert
24th November 2018,
9:52 AM
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