Please explain it iodine reacts in excess then what is the product
Asked by amitjena226
17th January 2018,
12:17 PM
Answered by Expert
Answer:
If HI adds to an unsymmetrical alkene like Propene, there are two possible ways it could add. However, in practice, there is only one major product.
According to Markovnikovs rule, When compound HX is added to an unsymmetrical alkene, become attached to the carbon with the most hydrogen attached to it already.
In this case, the hydrogen directly attached to the CH2 group, because the CH2 group has more hydrogens than the CH group.
Notice that only the hydrogens directly attached to the carbon atoms at either end of the doube bond count. the ones in the CH3 group are totally irrelevant.
Answered by Expert
17th January 2018,
1:26 PM
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