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Please answer the following question with explanation

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Asked by Deepak 12th September 2018, 10:08 PM
Answered by Expert
Answer:
Given:
 
CH3OH(l) + 3/2 O2 (g)  → CO2 (g) + 2H2O(l) 
 
ΔG0f CH3OH(l) = -237.2 kJ/mol
 
ΔG0f CO2 (g) = -394.4 kJ/mol
 
ΔG0f H2O(l)  = -237.2 kJ/mol
 
ΔG = ΣΔG0f products - ΣΔG0f reactants
 
      = [-394.4 -(2)(237.2)] + 166.2
 
ΔG  = -702.6 kJ/mol
 
Efficiency of fuel cell = space space space fraction numerator increment straight G over denominator increment straight H end fraction cross times 100

equals fraction numerator 702.6 over denominator 726 end fraction cross times 100

equals 96.77 percent sign
 
The efficiency of fuel cell is 96.7%.
 
Answered by Expert 13th September 2018, 8:00 PM
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