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plaese solve this problem

Asked by jaychandran1967 27th November 2017, 10:53 PM
Answered by Expert
Answer:

Question:-
A particle moves along the parabolic path x=y2+2y+2 in such a way that the y-component of the velocity vector remains 5m/s during the motion. The magnitude of the acceleration of the particle is
 
l e t space x equals space t
t a k i n g space d e r i v a t i v e s space w. r. t space space x

x space equals space y squared plus 2 y plus 2

1 equals 2 y fraction numerator d y over denominator d x end fraction plus 2 fraction numerator d y over denominator d x end fraction plus 0

fraction numerator d y over denominator d t end fraction equals fraction numerator 1 over denominator left parenthesis 2 y plus 2 right parenthesis end fraction equals 5

o n space s i m p l i f y i n g space w e space g e t

10 y plus 10 equals 1

y equals negative 0.9

A c c e l e r a t i o n equals space fraction numerator negative 0.5 over denominator left parenthesis y plus 1 right parenthesis squared end fraction

p u t space y equals negative 0.9

a c c e l e r a t i o n equals space 50 space m divided by s squared
Answered by Expert 28th November 2017, 5:01 PM
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