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Home / Doubts and Solutions/JEE/Physics

plaese solve this problem
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Asked by jaychandran1967 27th November 2017, 10:53 PM
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Question:-
A particle moves along the parabolic path x=y2+2y+2 in such a way that the y-component of the velocity vector remains 5m/s during the motion. The magnitude of the acceleration of the particle is
 
l e t space x equals space t t a k i n g space d e r i v a t i v e s space w. r. t space space x x space equals space y squared plus 2 y plus 2 1 equals 2 y fraction numerator d y over denominator d x end fraction plus 2 fraction numerator d y over denominator d x end fraction plus 0 fraction numerator d y over denominator d t end fraction equals fraction numerator 1 over denominator left parenthesis 2 y plus 2 right parenthesis end fraction equals 5 o n space s i m p l i f y i n g space w e space g e t 10 y plus 10 equals 1 y equals negative 0.9 A c c e l e r a t i o n equals space fraction numerator negative 0.5 over denominator left parenthesis y plus 1 right parenthesis squared end fraction p u t space y equals negative 0.9 a c c e l e r a t i o n equals space 50 space m divided by s squared
Answered by Expert 28th November 2017, 5:01 PM
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