Particle is dropped from the height of 20m on horizontal ground. There is wind blowing due to which horizontal acceleration of the particle becomes 6ms-1.Find the horizontal displacement of the particle till it reaches ground
Asked by valavanvino1011
14th August 2018,
4:24 AM
Answered by Expert
Answer:
I assume horizontal acceleration is 6 m/s2 . I assume g = 10 m/s2 for convenience of calculation.
when particle is dropped from 20m, the time to reach ground is calculated using " S = (1/2)gt2 ", because initial velocity is zero.
20 = (1/2)×10×t2 .............(1)
solving the above eqn.(1) for t, we get t = 2 s
horizontal distance D travelled in 2 seconds is also calculated using " D = (1/2)at2 ", where a is the acceleration 6 m/s2 .
D = (1/2)×6×2×2 = 12 m
Answered by Expert
14th August 2018,
11:08 AM
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