One end of a 2.35 m long and 2 cm radius aluminium rod(K=235WmK)is held at 20C the other end of the rod is in contanct withba block of ice at its melting point The rate in kg/s at ehich ice melts is(Take latent heat of fusion for ice as 10/3 ×10^5)
Asked by nipunverma59
4th October 2018,
6:41 PM
Answered by Expert
Answer:
Heat energy Q transferred to ice, Q = k×A×(dT/dx) ....................(1)
where k is thermal conductivity, A is area and dT/dx is temperature gradient
given data:- k = 235 W/(m-K) , A = π×2×2×10-4 m2 , dT/dx = (20/2.35) K/m
we get Q from eqn.(1) as, Q = 235×π×2×2×10-4×( 20 / 2.35 ) = 2.513 W
Let (m/t) is rate of amount of ice melting (kg/s) at 0ºC.
Then we have, (m/t)×L = 2.513 ................(2)
where L is latent heat of fusion of ice, L = (10/3)×105 J/kg
from eqn.(2) we get (m/t) 
Answered by Expert
4th October 2018,
8:12 PM
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