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Home / Doubts and Solutions/JEE/Physics

kindly solve (ref. 347)

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Asked by arup.isro 12th July 2018, 11:11 PM
Answered by Expert
Answer:
Figure shows how tension forces are acting on different parts of string.
 
We have T1  =  W and T2 sin 60 = T2 (√3 / 2 ) = W
 
Hence T2 = (2×W) / √3 ...................(1)
 
we have, T3 = T2 cos60 = [ (2×W) / √3 ]×(1/2)  = W/√3
 
since it is given that,breaking strength of string that has tension T3 , we write W = √3×175 N
Answered by Expert 14th July 2018, 3:45 PM
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