Please wait...
Contact Us
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry



Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

93219 24448 / 99871 78554

Mon to Sat - 10 AM to 7 PM

It's answer is 'a' of glucose and 'b' of fructose. Can you please explain? 

Asked by vidyuti.varma 26th June 2016, 11:09 PM
Answered by Expert
A carbohydrate exists in a cyclic or an acyclic form. During cyclization, the carbonyl carbon of monosaccharide transforms into a new stereocenter. Cyclization causes the formation of 2 new diasteriomers. They differ in the position of the attachment of a certain group to the new stereocenter. The new stereocenter is referred to as the anomeric carbon.
In the given problem, there are two monosaccharides such as glucose and fructose in the given disaccharides.
When fischer formula of these monosaccharides turns into cyclic stucture and form anomeric carbon.
How to locate the anomeric carbon in D-Glucose?
Step 1: Locate the oxygen inside the ring
Step 2: Look at the carbons on either side of the oxygen. One will be attached to a CH2OH group. Do not focus on this one. The carbon on the other side is the anomeric carbon.
Answered by Expert 28th June 2016, 10:34 AM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Free related questions


Chat with us on WhatsApp